>I have a Control that I want to copy as a copy of the Control, not a copy
>of the reference to the original. My reason for doing this is because some
>of the methods I would calling would prevent proper rendering afterwards. I
>access the Control as a parameter of a function, as follows:
>
> Private Function MyFunction(ByVal ctrl As Control) As String
> 'code that will make a copy of ctrl
> 'my function code
> End Function
>
> (NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.
> --
> Nathan Sokalski
> njsokalski@hotmail.com
> http://www.nathansokalski.com/
>

Nathan Sokalski wrote:

>I have a Control that I want to copy as a copy of the Control, not a copy of
>the reference to the original. My reason for doing this is because some of
>the methods I would calling would prevent proper rendering afterwards. I
>access the Control as a parameter of a function, as follows:
>
>Private Function MyFunction(ByVal ctrl As Control) As String
> 'code that will make a copy of ctrl
> 'my function code
>End Function
>
>(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.
>
>

"tomb" <tomb@technetcenter.com> wrote in message
news:RV5jg.71053$QU3.68250@bignews8.bellsouth.net...
> Nathan Sokalski wrote:
>
>>I have a Control that I want to copy as a copy of the Control, not a copy
>>of the reference to the original. My reason for doing this is because some
>>of the methods I would calling would prevent proper rendering afterwards.
>>I access the Control as a parameter of a function, as follows:
>>
>>Private Function MyFunction(ByVal ctrl As Control) As String
>> 'code that will make a copy of ctrl
>> 'my function code
>>End Function
>>
>>(NOTE: I am using VB.NET and .NET Framework 1.1) Thanks.
>>
> You have to pass the ctrl ByRef in order to be working with the one you
> want to copy.
>
> T