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That example will probably be the same in both notations. However, if
you have any more tables involved then things are trickier.

Here is how OUTER JOINs work in SQL-92. Assume you are given:

Table1 Table2
a b a c
====== ======
1 w 1 r
2 x 2 s
3 y 3 t
4 z

and the outer join expression:

Table1
LEFT OUTER JOIN
Table2
ON Table1.a = Table2.a <== join condition
AND Table2.c = 't'; <== single table condition

We call Table1 the "preserved table" and Table2 the "unpreserved table"
in the query. What I am going to give you is a little different, but
equivalent to the ANSI/ISO standards.

1) We build the CROSS JOIN of the two tables. Scan each row in the
result set.

2) If the predicate tests TRUE for that row, then you keep it. You also
remove all rows derived from it from the CROSS JOIN

3) If the predicate tests FALSE or UNKNOWN for that row, then keep the
columns from the preserved table, convert all the columns from the
unpreserved table to NULLs and remove the duplicates.

So let us execute this by hand:

Let @ = passed the first predicate
Let * = passed the second predicate

Table1 CROSS JOIN Table2
a b a c
=========================
1 w 1 r @
1 w 2 s
1 w 3 t *
2 x 1 r
2 x 2 s @
2 x 3 t *
3 y 1 r
3 y 2 s
3 y 3 t @* <== the TRUE set
4 z 1 r
4 z 2 s
4 z 3 t *

Table1 LEFT OUTER JOIN Table2
a b a c
=========================
3 y 3 t <= only TRUE row
-----------------------
1 w NULL NULL Sets of duplicates
1 w NULL NULL
1 w NULL NULL
-----------------------
2 x NULL NULL
2 x NULL NULL
2 x NULL NULL
3 y NULL NULL <== derived from the TRUE set - Remove
3 y NULL NULL
-----------------------
4 z NULL NULL
4 z NULL NULL
4 z NULL NULL

the final results:

Table1 LEFT OUTER JOIN Table2
a b a c
=========================
1 w NULL NULL
2 x NULL NULL
3 y 3 t
4 z NULL NULL

The basic rule is that every row in the preserved table is represented
in the results in at least one result row.

There are limitations and very serious problems with the extended
equality version of an outer join used in some diseased mutant products.
Consider the two Chris Date tables

Suppliers SupParts
supno supno partno qty
========= ==============
S1 S1 P1 100
S2 S1 P2 250
S3 S2 P1 100
S2 P2 250

and let's do an extended equality outer join like this:

SELECT *
FROM Supplier, SupParts
WHERE Supplier.supno *= SupParts.supno
AND qty < 200;

If I do the outer first, I get:

Suppliers LOJ SupParts
supno supno partno qty
=======================
S1 S1 P1 100
S1 S1 P2 250
S2 S2 P1 100
S2 S2 P2 250
S3 NULL NULL NULL

Then I apply the (qty < 200) predicate and get

Suppliers LOJ SupParts
supno supno partno qty
===================
S1 S1 P1 100
S2 S2 P1 100

Doing it in the opposite order

Suppliers LOJ SupParts
supno supno partno qty
===================
S1 S1 P1 100
S2 S2 P1 100
S3 NULL NULL NULL

Sybase does it one way, Oracle does it the other and Centura (nee Gupta)
lets you pick which one -- the worst of both non-standard worlds! In
SQL-92, you have a choice and can force the order of execution. Either
do the predicates after the join ...

SELECT *
FROM Supplier
LEFT OUTER JOIN
SupParts
ON Supplier.supno = SupParts.supno
WHERE qty < 200;

... or do it in the joining:

SELECT *
FROM Supplier
LEFT OUTER JOIN
SupParts
ON Supplier.supno = SupParts.supno
AND qty < 200;

Another problem is that you cannot show the same table as preserved and
unpreserved in the extended equality version, but it is easy in SQL-92.
For example to find the students who have taken Math 101 and might have
taken Math 102:

SELECT C1.student, C1.math, C2.math
FROM (SELECT * FROM Courses WHERE math = 101) AS C1
LEFT OUTER JOIN
(SELECT * FROM Courses WHERE math = 102) AS C2
ON C1.student = C2.student;

--CELKO--
===========================
Please post DDL, so that people do not have to guess what the keys,
constraints, Declarative Referential Integrity, datatypes, etc. in your
schema are.

*** Sent via Developersdex http://www.developersdex.com ***

Internally, they should be exactly the same. Any two queries that are
mathematically the same should end up to be optimized the same. In the case
of such a simple query, there is little chance that they would be dealt with
differently internally.

The new syntax is merely much more expressive and allows more freedom in
what it allows. Most notably in the old syntax a table could not be a part
of a left and a right outer join at the same time. Plus full outer joins
were introduced.

--
----------------------------------------------------------------------------
-----------
Louis Davidson (drsql@hotmail.com)
Compass Technology Management

Pro SQL Server 2000 Database Design
http://www.apress.com/book/bookDisplay.html?bID=266

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