List in order -- sql server programming

sql server programming : List in order

Hassan
3/13/2005 10:41:21 PM

Say I have a table with the following files in them but not sorted and I
wanted to sort them in order like these based on the timestamp part of it.
How can I do so ?

DB1_tlog_200503122235.TRN
DB1_tlog_200503122240.TRN
DB1_tlog_200503122245.TRN
DB1_tlog_200503122250.TRN
DB1_tlog_200503122255.TRN
DB1_tlog_200503122300.TRN
DB1_tlog_200503122305.TRN
DB1_tlog_200503122310.TRN
DB1_tlog_200503122315.TRN

I think we need to find the datetime portion and that would be before the
".trn" and after the "_tlog_"

And then be able to sort the string "200503122235" which represents
2005-03-12 22:35 .. How can I do this ?

Thanks

Daniel Crichton
3/14/2005 9:18:32 AM

[quoted text, click to view]

If all of the filenames have the same prefix and extension, and all use the
above format for the date/time part, then it's simply a case of ordering the
results by that column. The date/time formatting is already fine for
sorting, so there's no need to convert it to a real date/time.

Dan

Uri Dimant
3/14/2005 9:49:45 AM

Hassan
drop table #tEST
CREATE TABLE #Test
(
col VARCHAR(50) NOT NULL
)
INSERT INTO #Test VALUES ('200503122235')
INSERT INTO #Test VALUES ('200503122138')
INSERT INTO #Test VALUES ('200503121845')
INSERT INTO #Test VALUES ('200503122125')
INSERT INTO #Test VALUES ('200503122030')
INSERT INTO #Test VALUES ('200503122430')

SELECT *
FROM #Test
ORDER BY CONVERT(DATETIME,LEFT(col,4)+SUBSTRING(col,5,2)+
SUBSTRING(col,8,2)+'
'+REPLACE(SUBSTRING(col,9,2),'24','00')+':'+SUBSTRING(col,11,2) ,112)

[quoted text, click to view]

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