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Re: Join?

Johnny D
4/23/2006 8:55:55 PM

sql server programming: As far as I can tell all you need is...

SELECT t1.Answer , t1.QuestionID , t1.CustomerID
, t2.CustomerID, t2.IEventID, t2.IEDescription
FROM customerquestions t1 FULL OUTER JOIN t2
ON ( t1.CustomerID=t2.CustomerID)

I do not know what your table names are so i Put in some guesses..

Join?

Brad Baker
4/23/2006 11:15:54 PM

I have the following two tables of data:

Answer QuestionID CustomerID
------ ---------- ----------
Answer1 15 5090
Answer2 14 5090
Answer3 14 5090
Answer4 15 5091
Answer5 14 5091
Answer6 14 5091

CustomerID IEventID IEDescription
---------- -------- -------------
5090 1 TEST1
5091 2 TEST2

As you can see there is a similar field between the two tables (CustomerID).
My problem is that I need to merge these two tables into one table. I could
use a simple join statement but then I would end up with 6 unique records. I
need two unique records - something like this:

IECustomerID IEventID IEDescription ? ?
?
------------ -------- ------------- ------
------- -------
5090 1 TEST1 Answer1
Answer2 Answer3
5091 2 TEST2 Answer4
Answer5 Answer6

I want to output the results using an ASP.NET repeater. Is there a way to do
what I want? Am I looking at this in the wrong way? Or is this just
impossible? Any guidance or assistance anyone could provide would be
appreciated.

Thank You,
Brad

Re: Join?

Colin Dawson
4/24/2006 12:00:00 AM

You'll need to use a pivot function for this. But, there is a problem with
the table design. The problem is that there is no way to distinguish
between Answer2 and Answer3, also the same problem exists for Answer5 &
Answer6. Once you sort that problem out perfoming a pivot will be easy.

To perform the Pivot either use the PIVOT command in SQL2005, or in SQL2000
use syntax like this....

Select
CustomerID,
Max( Case When QuestionID = 15 then Answer Else null ) AnswerToQestion15,
Max( Case When QuestionID = 14 then Answer Else null )
swerToQestion14, -- note: This will only return ONE answer.
From Table1
Group By CustomerID

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