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dotnet drawing api : Two newbie questions
1. PaintEventArgs.Graphics.Drawstring() need to specify the upper-left
coordinate for the text to be drawn. What measure unit should be used for the coordinate? 2. Why the following piece of code can't print the Texts (on letter paper)? However, if remove the "e.Graphics.PageUnit=GraphicsUnit.Inch;" and set 0.5F/0.6F to be 0.5*100 and 0.6*100 can work. private void printDocument1_PrintPage(object sender, PrintPageEventArgs e) { Font newFont= new System.Drawing.Font("Arial", 10F, System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, ((System.Byte)(134))); e.Graphics.PageUnit=GraphicsUnit.Inch;// float leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); float topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); e.Graphics.DrawString(this.textBox1.Text, this.textBox1.Font, Brushes.Black, leftInch, topInch); e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F);
When I comment out to be the following, it still doesnot work. The
leftInch=3.5 inch, the topInch=3.8inch. When I further comment out the leftInch and rightInch statements, it prints. What's the reason? private void printDocument1_PrintPage(object sender, PrintPageEventArgs e) { Font newFont= new System.Drawing.Font("Arial", 10F, System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, ((System.Byte)(134))); e.Graphics.PageUnit=GraphicsUnit.Inch;// float leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); float topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F); } Another question: the destination and source rectangles in PaintEventrgs.DrawImage() should be in measure unit defined by the GraphicsUnit parameter or by the external e.Graphics.PageUnit? Does DrawString takes the rectangle or pointF parameters in measure unit defined by Font's emsize generaly in Point or by the external e.Graphics.PageUnit? [quoted text, click to view] "Bob Powell [MVP]" wrote:
> If you're printing then a real-world measurement system such as points, > millimeters or inches is best. > > Remember that the printer bounds are declared in 100ths of an inch. NOT > pixels. You need to multiply the printer bounds by the DPI to get the real > pixel count if you want to use pixels at-all. > > I haven't the faintest idea what sort of values you're producing with your > calculations on how the reciprocal width of a picturebox has a relation to > the left edge of a textbox. This is more esoteric than quantum physics. The > text doesn't show up because the result of that calculation puts it outside > the page margins obviously. > > -- > Bob Powell [MVP] > Visual C#, System.Drawing > > Find great Windows Forms articles in Windows Forms Tips and Tricks > http://www.bobpowell.net/tipstricks.htm > > Answer those GDI+ questions with the GDI+ FAQ > http://www.bobpowell.net/faqmain.htm > > All new articles provide code in C# and VB.NET. > Subscribe to the RSS feeds provided and never miss a new article. > > > > > > "zhaounknown" <zhaounknown@discussions.microsoft.com> wrote in message > news:7A138DA2-2217-4C11-8BDC-C1B879506E08@microsoft.com... > > 1. PaintEventArgs.Graphics.Drawstring() need to specify the upper-left > > coordinate for the text to be drawn. What measure unit should be used for > > the > > coordinate? > > > > 2. Why the following piece of code can't print the Texts (on letter > > paper)? > > However, if remove the "e.Graphics.PageUnit=GraphicsUnit.Inch;" and set > > 0.5F/0.6F to be 0.5*100 and 0.6*100 can work. > > > > private void printDocument1_PrintPage(object sender, PrintPageEventArgs e) > > { > > Font newFont= new System.Drawing.Font("Arial", 10F, > > System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, > > ((System.Byte)(134))); > > > > e.Graphics.PageUnit=GraphicsUnit.Inch;// > > float > > leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); > > float > > topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); > > > > e.Graphics.DrawString(this.textBox1.Text, this.textBox1.Font, > > Brushes.Black, > > leftInch, topInch); > > > > e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F); > > } > >
If you're printing then a real-world measurement system such as points,
millimeters or inches is best. Remember that the printer bounds are declared in 100ths of an inch. NOT pixels. You need to multiply the printer bounds by the DPI to get the real pixel count if you want to use pixels at-all. I haven't the faintest idea what sort of values you're producing with your calculations on how the reciprocal width of a picturebox has a relation to the left edge of a textbox. This is more esoteric than quantum physics. The text doesn't show up because the result of that calculation puts it outside the page margins obviously. -- Bob Powell [MVP] Visual C#, System.Drawing Find great Windows Forms articles in Windows Forms Tips and Tricks http://www.bobpowell.net/tipstricks.htm Answer those GDI+ questions with the GDI+ FAQ http://www.bobpowell.net/faqmain.htm All new articles provide code in C# and VB.NET. Subscribe to the RSS feeds provided and never miss a new article. [quoted text, click to view] "zhaounknown" <zhaounknown@discussions.microsoft.com> wrote in message news:7A138DA2-2217-4C11-8BDC-C1B879506E08@microsoft.com... > 1. PaintEventArgs.Graphics.Drawstring() need to specify the upper-left > coordinate for the text to be drawn. What measure unit should be used for > the > coordinate? > > 2. Why the following piece of code can't print the Texts (on letter > paper)? > However, if remove the "e.Graphics.PageUnit=GraphicsUnit.Inch;" and set > 0.5F/0.6F to be 0.5*100 and 0.6*100 can work. > > private void printDocument1_PrintPage(object sender, PrintPageEventArgs e) > { > Font newFont= new System.Drawing.Font("Arial", 10F, > System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, > ((System.Byte)(134))); > > e.Graphics.PageUnit=GraphicsUnit.Inch;// > float > leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); > float > topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); > > e.Graphics.DrawString(this.textBox1.Text, this.textBox1.Font, > Brushes.Black, > leftInch, topInch); > > e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F); > }
Hmm, I suspect that you're actually throwing an exception because of a
divide by zero or some such thing and catching it someplace else. Have you put an application exception handler in somewhere? -- Bob Powell [MVP] Visual C#, System.Drawing Ramuseco Limited .NET consulting http://www.ramuseco.com Find great Windows Forms articles in Windows Forms Tips and Tricks http://www.bobpowell.net/tipstricks.htm Answer those GDI+ questions with the GDI+ FAQ http://www.bobpowell.net/faqmain.htm All new articles provide code in C# and VB.NET. Subscribe to the RSS feeds provided and never miss a new article. [quoted text, click to view] "zhaounknown" <zhaounknown@discussions.microsoft.com> wrote in message news:9B188AC6-3884-41FB-8F6E-AB6D7E25788D@microsoft.com... > When I comment out to be the following, it still doesnot work. The > leftInch=3.5 inch, the topInch=3.8inch. When I further comment out the > leftInch and rightInch statements, it prints. What's the reason? > > private void printDocument1_PrintPage(object sender, PrintPageEventArgs e) > { > Font newFont= new System.Drawing.Font("Arial", 10F, > System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, > ((System.Byte)(134))); > > e.Graphics.PageUnit=GraphicsUnit.Inch;// > float > leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); > float > topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); > > e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F); > } > > Another question: the destination and source rectangles in > PaintEventrgs.DrawImage() should be in measure unit defined by the > GraphicsUnit parameter or by the external e.Graphics.PageUnit? > > Does DrawString takes the rectangle or pointF parameters in measure unit > defined by Font's emsize generaly in Point or by the external > e.Graphics.PageUnit? > > "Bob Powell [MVP]" wrote: > >> If you're printing then a real-world measurement system such as points, >> millimeters or inches is best. >> >> Remember that the printer bounds are declared in 100ths of an inch. NOT >> pixels. You need to multiply the printer bounds by the DPI to get the >> real >> pixel count if you want to use pixels at-all. >> >> I haven't the faintest idea what sort of values you're producing with >> your >> calculations on how the reciprocal width of a picturebox has a relation >> to >> the left edge of a textbox. This is more esoteric than quantum physics. >> The >> text doesn't show up because the result of that calculation puts it >> outside >> the page margins obviously. >> >> -- >> Bob Powell [MVP] >> Visual C#, System.Drawing >> >> Find great Windows Forms articles in Windows Forms Tips and Tricks >> http://www.bobpowell.net/tipstricks.htm >> >> Answer those GDI+ questions with the GDI+ FAQ >> http://www.bobpowell.net/faqmain.htm >> >> All new articles provide code in C# and VB.NET. >> Subscribe to the RSS feeds provided and never miss a new article. >> >> >> >> >> >> "zhaounknown" <zhaounknown@discussions.microsoft.com> wrote in message >> news:7A138DA2-2217-4C11-8BDC-C1B879506E08@microsoft.com... >> > 1. PaintEventArgs.Graphics.Drawstring() need to specify the upper-left >> > coordinate for the text to be drawn. What measure unit should be used >> > for >> > the >> > coordinate? >> > >> > 2. Why the following piece of code can't print the Texts (on letter >> > paper)? >> > However, if remove the "e.Graphics.PageUnit=GraphicsUnit.Inch;" and set >> > 0.5F/0.6F to be 0.5*100 and 0.6*100 can work. >> > >> > private void printDocument1_PrintPage(object sender, PrintPageEventArgs >> > e) >> > { >> > Font newFont= new System.Drawing.Font("Arial", 10F, >> > System.Drawing.FontStyle.Bold, System.Drawing.GraphicsUnit.Point, >> > ((System.Byte)(134))); >> > >> > e.Graphics.PageUnit=GraphicsUnit.Inch;// >> > float >> > leftInch=(float)(this.textBox1.Left*1.0/this.pictureBox1.Image.Width*8.5); >> > float >> > topInch=(float)(this.textBox1.Top*1.0/this.pictureBox1.Image.Height*11.0); >> > >> > e.Graphics.DrawString(this.textBox1.Text, this.textBox1.Font, >> > Brushes.Black, >> > leftInch, topInch); >> > >> > e.Graphics.DrawString("X", newFont, Brushes.Black, 0.5F, 0.6F); >> > } >> >> >>
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