>I have no problems in selecting the non-rectangular region - this is easy.
>I'm stumped at trying to work out how to take this region and applying the
>Photoshop like Distort Transformation.

"Oliver Sturm" <oliver@sturmnet.org> wrote in message
news:xn0f1pol92eb11y005@msnews.microsoft.com...
> Hello GraGra33,
>
>>I have no problems in selecting the non-rectangular region - this is easy.
>>I'm stumped at trying to work out how to take this region and applying the
>>Photoshop like Distort Transformation.
>
> That's why they charge you so much for Photoshop :-) Seriously, I believe
> you'll have to find a mathemetical algorithm to perform that kind of
> transformation operation. There are some resources on the web advanced
> graphical operations, so you may be able to find something there -
> otherwise of course you can come up with your own algorithm, with probably
> questionable results. I mean, it would be pretty easy to do the job using
> a column by column approach - but then that may look stupid. You could go
> row by row, but that may look just as stupid. I wonder if it would be a
> good idea calculating both column by column and row by row results and
> "merge" those together somehow... as I said, this is exactly the kind of
> work that the Photoshop people already did, and that they charge you for.
>
> All that said, maybe it would be a much easier way to remote control
> Photoshop for the purpose? I don't really know that application
> intimately, but maybe they have an automation model? Or even a
> comprehensive set of command line options?
>
>
> Oliver Sturm
> --
> http://www.sturmnet.org/blog