Thanks. I'm going to work on this tonight, and let you know if this does the
"Bruce Barker" wrote:
> the trick is to reinsert the rows with appendChild(). if you put a tbody on
> the table it will be easier to find the starting row.
>
> <html>
> <body>
> <script>
> function reverse(table) {
> var tbody = table.tBodies[0];
> var rows = tbody.childNodes;
> var a = new Array();
> for (var i=0; i<rows.length; i++) {
> a[i] = rows[i];
> }
> for (var i=a.length-1; i > -1; --i) {
> tbody.appendChild(a[i]);
> }
> }
> </script>
> <table id=foo onclick="reverse(this)">
> <thead>
> <tr><th>col1</th><th>col2</th><th>col3</th></tr>
> </thead>
> <tbody>
> <tr><td>a1</td><td>b1</td><td>c1</td>
> <tr><td>a2</td><td>b2</td><td>c2</td>
> <tr><td>a3</td><td>b3</td><td>c3</td>
> </tbody>
> </table>
> <body>
> </html>
>
>
> -- bruce (sqlwork.com)
>
>
> "Brian Kitt" <BrianKitt@discussions.microsoft.com> wrote in message
> news:4A1698DF-1D0E-4777-B44C-CC9CEE8C536E@microsoft.com...
> >I have a website that displays data in a table. It takes about 30 seconds
> >to
> > build the display from the server because of the amount of cpu and data
> > access needed to build the table. Each row of the table itself consists
> > of a
> > variable number of elements, including zero or more tables.
> >
> > My customer wants to be able to click on a button and sort the resulting
> > table. They don't want me to go back to the server to rebuild the table
> > because of the time it takes to build the table, they want it sorted in
> > place.
> >
> > Problem I am running into, is trying to figure out how to swap rows in the
> > table. I have a unique id for each row in the table, but because the rows
> > are so complex, everything I have tried so far just results in runtime
> > errors.
> >
> > I've tried the following: (given Row1 and Row2 need to be swapped)
> > Row1.innerHTML = Row2.innerHTML = Results in run time error
> > Row1.outerHTML = Row2.outerHTML = Results in run time error
> > Row1 = Row2 = no error, but seems to have no effect
> > Row1.innerText = Row2.innerText = not an option because of the complexity.
> > I've tried looping through childNodes of Row1 and setting them to
> > childNodes
> > of Row2, but the problem I run into, is that Row1 and Row2 are not
> > guaranteed
> > to have the same number of childNodes, and this results in failure as
> > well.
> >
> > Any other ideas?
>
>
