On Feb 21, 2:36 pm, "Armin Zingler" <az.nos...@freenet.de> wrote:
> "Spam Catcher" <spamhoney...@rogers.com> schrieb
>
> > Hi all
>
> > When .NET fires and event, does the event handler execute under a
> > new thread, or does it execute under the primary application thread?
>
> The event handler runs in the same thread as the code that raises the event.
> No thread is created. The event handler is just a function called.
>
> > Basically if I have events firing, do the event handlers themselves
> > need to spawn need threads, or can I safely assume the event handler
> > is already running under a new thread?
>
> If you want to run something in a new thread each time the event handler is
> called, you must start the thread on you own.
>
> Armin

On 2007-02-21, Spam Catcher <spamhoneypot@rogers.com> wrote:
> "Tom Shelton" <tom_shelton@comcast.net> wrote in
> news:1172094489.837789.178250@q2g2000cwa.googlegroups.com:
>
>> Or run the delegate asycronously using BeginInvoke - in that case, the
>> method will be called on a thread from the thread pool.
>
> If I do so, I'll have to call EndInvoke correct?
>

> The event handler runs in the same thread as the code that raises the
> event. No thread is created. The event handler is just a function
> called.
>
>> Basically if I have events firing, do the event handlers themselves
>> need to spawn need threads, or can I safely assume the event handler
>> is already running under a new thread?
>
> If you want to run something in a new thread each time the event
> handler is called, you must start the thread on you own.

> Hi all
>
>
> When .NET fires and event, does the event handler execute under a
> new thread, or does it execute under the primary application thread?

> Basically if I have events firing, do the event handlers themselves
> need to spawn need threads, or can I safely assume the event handler
> is already running under a new thread?

> Or run the delegate asycronously using BeginInvoke - in that case, the
> method will be called on a thread from the thread pool.