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dotnet xml : SORTING A FILE XML
is it possible to sort a XML file without using a XSLT or XSL file?? For example, my XML is: <A> <1> <3> <4> <2> </A> <C> <2> <1> </C> <B> <3> <2> <1> </B> The result of the sorting method should by: <A> <1> <2> <3> <4> </A> <B> <1> <2> <3> </B> <C> <1> <2> </C> Can anyone help me ?
Hi Martin,
thanks for answering. You're right... I've written a bat example.... my real XML file is like this: - <APPLICATIONLIST> - <APPLICATION APPNAME="ActiveSync"> - <ICONGROUP SOURCE="ActiveSync.lnk"> - <DEST TARGET="START" /> </ICONGROUP> </APPLICATION> - <APPLICATION APPNAME="AutoCAD"> - <ICONGROUP SOURCE="AutoCAD.lnk"> <DEST TARGET="START" /> </ICONGROUP> </APPLICATION> - <APPLICATION APPNAME="Banana"> - <ICONGROUP SOURCE="Banana.lnk"> <DEST TARGET="START" /> </ICONGROUP> </APPLICATION> - <APPLICATION APPNAME="Bridge Workstation"> </APPLICATION> <APPLICATIONLIST> I would like to order my XML file by APPNAME of each APPLICATION node: the latter can be also nested into other APPLICATION node, like this: - <APPLICATION APPNAME="MicrosoftOffice"> - <ICONGROUP SOURCE="ActiveSync.lnk"> - <DEST TARGET="START" /> </ICONGROUP> - <APPLICATION APPNAME="Excel"/> - <APPLICATION APPNAME="Word"/> - <APPLICATION APPNAME="PowerPoint"/> </APPLICATION> Can you help me, please [quoted text, click to view] "Martin Honnen" wrote:
> > > Siu wrote: > > > > is it possible to sort a XML file without using a XSLT or XSL file?? > > Yes, there are other ways to programmatically manipulate XML, DOM > programming for instance, see System.Xml.XmlDocument. But XSLT has a > sort instruction while with DOM programming you need to implement that > yourself. > > > For example, my XML is: > > > > <A> > > <1> > > <3> > > <4> > > <2> > > </A> > > <C> > > <2> > > <1> > > </C> > > <B> > > <3> > > <2> > > <1> > > </B> > > That is not XML, you have no root element and element names need to > start with a letter and not a digit so you need to provide a sample that > is XML. > > > The result of the sorting method should by: > > <A> > > <1> > > <2> > > <3> > > <4> > > </A> > > <B> > > <1> > > <2> > > <3> > > </B> > > <C> > > <1> > > <2> > > </C> > > So you want to sort by element names and not element content? Or is > <1> > supposed to be > <data>1</data> > ? > > -- > > Martin Honnen > http://JavaScript.FAQTs.com/
[quoted text, click to view] Siu wrote: [quoted text, click to view] > is it possible to sort a XML file without using a XSLT or XSL file?? Yes, there are other ways to programmatically manipulate XML, DOM programming for instance, see System.Xml.XmlDocument. But XSLT has a sort instruction while with DOM programming you need to implement that yourself. [quoted text, click to view] > For example, my XML is: > > <A> > <1> > <3> > <4> > <2> > </A> > <C> > <2> > <1> > </C> > <B> > <3> > <2> > <1> > </B> That is not XML, you have no root element and element names need to start with a letter and not a digit so you need to provide a sample that is XML. [quoted text, click to view] > The result of the sorting method should by: > <A> > <1> > <2> > <3> > <4> > </A> > <B> > <1> > <2> > <3> > </B> > <C> > <1> > <2> > </C> So you want to sort by element names and not element content? Or is <1> supposed to be <data>1</data> ? -- Martin Honnen
[quoted text, click to view] Siu wrote: [quoted text, click to view] > my real > XML file is like this: > > - <APPLICATIONLIST> > - <APPLICATION APPNAME="ActiveSync"> > - <ICONGROUP SOURCE="ActiveSync.lnk"> > - <DEST TARGET="START" /> > </ICONGROUP> > </APPLICATION> > - <APPLICATION APPNAME="AutoCAD"> > - <ICONGROUP SOURCE="AutoCAD.lnk"> > <DEST TARGET="START" /> > </ICONGROUP> > </APPLICATION> > - <APPLICATION APPNAME="Banana"> > - <ICONGROUP SOURCE="Banana.lnk"> > <DEST TARGET="START" /> > </ICONGROUP> > </APPLICATION> > - <APPLICATION APPNAME="Bridge Workstation"> > </APPLICATION> > <APPLICATIONLIST> > > I would like to order my XML file by APPNAME of each APPLICATION node: the > latter can be also nested into other APPLICATION node, like this: > > - <APPLICATION APPNAME="MicrosoftOffice"> > - <ICONGROUP SOURCE="ActiveSync.lnk"> > - <DEST TARGET="START" /> > </ICONGROUP> > - <APPLICATION APPNAME="Excel"/> > - <APPLICATION APPNAME="Word"/> > - <APPLICATION APPNAME="PowerPoint"/> > </APPLICATION> Here is an XSLT 1.0 stylesheet that sorts that: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" encoding="UTF-8" indent="yes" /> <xsl:template match="@* | node()"> <xsl:copy> <xsl:apply-templates select="@* | node()" /> </xsl:copy> </xsl:template> <xsl:template match="APPLICATIONLIST"> <xsl:copy> <xsl:apply-templates select="APPLICATION"> <xsl:sort select="@APPNAME" data-type="text" order="ascending" lang="en" case-order="upper-first" /> </xsl:apply-templates> </xsl:copy> </xsl:template> <xsl:template match="APPLICATION"> <xsl:copy> <xsl:apply-templates select="@*" /> <xsl:apply-templates select="ICONGROUP" /> <xsl:apply-templates select="APPLICATION"> <xsl:sort select="@APPNAME" data-type="text" order="ascending" lang="en" case-order="upper-first" /> </xsl:apply-templates> </xsl:copy> </xsl:template> </xsl:stylesheet> It is easily possible with .NET to apply the transformation to the source input, see the XslTransform class in the .NET documentation. -- Martin Honnen
Hi Martin,
your suggestion is perfect, thank you:) I've have another little question: I've used the XslTransform class in order to sort that xml file into another new xml file, and it works, but the problem is that the method or the xslt file writes into the output file as first row this: <?xml version="1.0" encoding="utf-8" ?> How can I avoid writing this row? Thank you again [quoted text, click to view] "Martin Honnen" wrote:
> > > Siu wrote: > > > > my real > > XML file is like this: > > > > - <APPLICATIONLIST> > > - <APPLICATION APPNAME="ActiveSync"> > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > - <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="AutoCAD"> > > - <ICONGROUP SOURCE="AutoCAD.lnk"> > > <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="Banana"> > > - <ICONGROUP SOURCE="Banana.lnk"> > > <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="Bridge Workstation"> > > </APPLICATION> > > <APPLICATIONLIST> > > > > I would like to order my XML file by APPNAME of each APPLICATION node: the > > latter can be also nested into other APPLICATION node, like this: > > > > - <APPLICATION APPNAME="MicrosoftOffice"> > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > - <DEST TARGET="START" /> > > </ICONGROUP> > > - <APPLICATION APPNAME="Excel"/> > > - <APPLICATION APPNAME="Word"/> > > - <APPLICATION APPNAME="PowerPoint"/> > > </APPLICATION> > > Here is an XSLT 1.0 stylesheet that sorts that: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="1.0"> > > <xsl:output method="xml" encoding="UTF-8" indent="yes" /> > > <xsl:template match="@* | node()"> > <xsl:copy> > <xsl:apply-templates select="@* | node()" /> > </xsl:copy> > </xsl:template> > > <xsl:template match="APPLICATIONLIST"> > <xsl:copy> > <xsl:apply-templates select="APPLICATION"> > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > lang="en" case-order="upper-first" /> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > <xsl:template match="APPLICATION"> > <xsl:copy> > <xsl:apply-templates select="@*" /> > <xsl:apply-templates select="ICONGROUP" /> > <xsl:apply-templates select="APPLICATION"> > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > lang="en" case-order="upper-first" /> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > </xsl:stylesheet> > > It is easily possible with .NET to apply the transformation to the > source input, see the XslTransform class in the .NET documentation. > > -- > > Martin Honnen > http://JavaScript.FAQTs.com/
Hi Martin,
your suggestion is perfect, thank you :) I've another question: I've used the method XslTransform in order to sort my xml file into another xml output file: in the latter appears as first row/sentence this: <?xml version="1.0" encoding="utf-8" ?> How can I avoid writing this first row/sentence? is it possible? Thank you again :) [quoted text, click to view] "Siu" wrote:
> Hi Martin, > your suggestion is perfect, thank you:) > > I've have another little question: I've used the XslTransform class in order > to sort that xml file into another new xml file, and it works, but the > problem is that the method or the xslt file writes into the output file as > first row this: > > <?xml version="1.0" encoding="utf-8" ?> > > How can I avoid writing this row? > > Thank you again > > "Martin Honnen" wrote: > > > > > > > Siu wrote: > > > > > > > my real > > > XML file is like this: > > > > > > - <APPLICATIONLIST> > > > - <APPLICATION APPNAME="ActiveSync"> > > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > > - <DEST TARGET="START" /> > > > </ICONGROUP> > > > </APPLICATION> > > > - <APPLICATION APPNAME="AutoCAD"> > > > - <ICONGROUP SOURCE="AutoCAD.lnk"> > > > <DEST TARGET="START" /> > > > </ICONGROUP> > > > </APPLICATION> > > > - <APPLICATION APPNAME="Banana"> > > > - <ICONGROUP SOURCE="Banana.lnk"> > > > <DEST TARGET="START" /> > > > </ICONGROUP> > > > </APPLICATION> > > > - <APPLICATION APPNAME="Bridge Workstation"> > > > </APPLICATION> > > > <APPLICATIONLIST> > > > > > > I would like to order my XML file by APPNAME of each APPLICATION node: the > > > latter can be also nested into other APPLICATION node, like this: > > > > > > - <APPLICATION APPNAME="MicrosoftOffice"> > > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > > - <DEST TARGET="START" /> > > > </ICONGROUP> > > > - <APPLICATION APPNAME="Excel"/> > > > - <APPLICATION APPNAME="Word"/> > > > - <APPLICATION APPNAME="PowerPoint"/> > > > </APPLICATION> > > > > Here is an XSLT 1.0 stylesheet that sorts that: > > > > <?xml version="1.0" encoding="UTF-8"?> > > <xsl:stylesheet > > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > > version="1.0"> > > > > <xsl:output method="xml" encoding="UTF-8" indent="yes" /> > > > > <xsl:template match="@* | node()"> > > <xsl:copy> > > <xsl:apply-templates select="@* | node()" /> > > </xsl:copy> > > </xsl:template> > > > > <xsl:template match="APPLICATIONLIST"> > > <xsl:copy> > > <xsl:apply-templates select="APPLICATION"> > > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > > lang="en" case-order="upper-first" /> > > </xsl:apply-templates> > > </xsl:copy> > > </xsl:template> > > > > <xsl:template match="APPLICATION"> > > <xsl:copy> > > <xsl:apply-templates select="@*" /> > > <xsl:apply-templates select="ICONGROUP" /> > > <xsl:apply-templates select="APPLICATION"> > > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > > lang="en" case-order="upper-first" /> > > </xsl:apply-templates> > > </xsl:copy> > > </xsl:template> > > > > </xsl:stylesheet> > > > > It is easily possible with .NET to apply the transformation to the > > source input, see the XslTransform class in the .NET documentation. > > > > -- > > > > Martin Honnen > > http://JavaScript.FAQTs.com/
Hi Martin,
your suggestion is perfect, thank you :) I've another question: I've used the method XslTransform in order to sort my xml file into another xml output file: in the latter appears as first row/sentence this: <?xml version="1.0" encoding="utf-8" ?> How can I avoid writing this first row/sentence? is it possible? Thank you again :) [quoted text, click to view] "Martin Honnen" wrote:
> > > Siu wrote: > > > > my real > > XML file is like this: > > > > - <APPLICATIONLIST> > > - <APPLICATION APPNAME="ActiveSync"> > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > - <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="AutoCAD"> > > - <ICONGROUP SOURCE="AutoCAD.lnk"> > > <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="Banana"> > > - <ICONGROUP SOURCE="Banana.lnk"> > > <DEST TARGET="START" /> > > </ICONGROUP> > > </APPLICATION> > > - <APPLICATION APPNAME="Bridge Workstation"> > > </APPLICATION> > > <APPLICATIONLIST> > > > > I would like to order my XML file by APPNAME of each APPLICATION node: the > > latter can be also nested into other APPLICATION node, like this: > > > > - <APPLICATION APPNAME="MicrosoftOffice"> > > - <ICONGROUP SOURCE="ActiveSync.lnk"> > > - <DEST TARGET="START" /> > > </ICONGROUP> > > - <APPLICATION APPNAME="Excel"/> > > - <APPLICATION APPNAME="Word"/> > > - <APPLICATION APPNAME="PowerPoint"/> > > </APPLICATION> > > Here is an XSLT 1.0 stylesheet that sorts that: > > <?xml version="1.0" encoding="UTF-8"?> > <xsl:stylesheet > xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > version="1.0"> > > <xsl:output method="xml" encoding="UTF-8" indent="yes" /> > > <xsl:template match="@* | node()"> > <xsl:copy> > <xsl:apply-templates select="@* | node()" /> > </xsl:copy> > </xsl:template> > > <xsl:template match="APPLICATIONLIST"> > <xsl:copy> > <xsl:apply-templates select="APPLICATION"> > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > lang="en" case-order="upper-first" /> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > <xsl:template match="APPLICATION"> > <xsl:copy> > <xsl:apply-templates select="@*" /> > <xsl:apply-templates select="ICONGROUP" /> > <xsl:apply-templates select="APPLICATION"> > <xsl:sort select="@APPNAME" data-type="text" order="ascending" > lang="en" case-order="upper-first" /> > </xsl:apply-templates> > </xsl:copy> > </xsl:template> > > </xsl:stylesheet> > > It is easily possible with .NET to apply the transformation to the > source input, see the XslTransform class in the .NET documentation. > > -- > > Martin Honnen > http://JavaScript.FAQTs.com/
Thank you very much, Martin ;)
[quoted text, click to view] "Martin Honnen" wrote:
> > > Siu wrote: > > > > I've have another little question: I've used the XslTransform class in order > > to sort that xml file into another new xml file, and it works, but the > > problem is that the method or the xslt file writes into the output file as > > first row this: > > > > <?xml version="1.0" encoding="utf-8" ?> > > > > How can I avoid writing this row? > > It is not a row, it is the XML declaration that usually doesn't do any > harm in an XML file. > If you want to avoid it you can do so from XSLT with > > <xsl:output method="xml" encoding="UTF-8" indent="yes" > omit-xml-declaration="yes" /> > > > -- > > Martin Honnen > http://JavaScript.FAQTs.com/
[quoted text, click to view] Siu wrote: [quoted text, click to view] > I've have another little question: I've used the XslTransform class in order > to sort that xml file into another new xml file, and it works, but the > problem is that the method or the xslt file writes into the output file as > first row this: > > <?xml version="1.0" encoding="utf-8" ?> > > How can I avoid writing this row? It is not a row, it is the XML declaration that usually doesn't do any harm in an XML file. If you want to avoid it you can do so from XSLT with <xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="yes" /> -- Martin Honnen
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