Hello,
I have a page in .net (DEFAULT.ASPX), i load a XmlDocument, and a
XslTransform to Add a XsltArgumentList (with the param : urlPage), and send
all to a <asp:xml> in the page.
The <asp:xml> is good with xml and xsl, but the param is not fill with the
value ?
Do you have a solution ??? Thanx
---
DEFAULT.ASPX :
<script language="C#" runat="server">
private void Page_Load(object sender, System.EventArgs e)
{
String xmlPath = Server.MapPath("/data/page.xml") ;
String xslPath = Server.MapPath("/xsl/i_infoPage.xsl") ;
String strUrlPage = "/default.aspx";
String xpathPage = "page[url='" + strUrlPage + "']";
// Nouvo XmlDoc pour l'affichage des Infos de Page
XmlDocument xmldocInfo = new XmlDocument();
xmldocInfo.Load(xmlPath);
XslTransform xsltInfo = new XslTransform();
xsltInfo.Load(xslPath);
// Crée un Arg pour le passage en Xslt du Composant Asp:Xml
XsltArgumentList argsInfo = new XsltArgumentList();
argsInfo.AddParam("urlPage","", "'Nico'");
// Réalise la transformation
xsltInfo.Transform(xmldocInfo, argsInfo);
// Source Xml et Xslt pour le Composant AspXml
aspxmlInfo.Document = xmldocInfo;
aspxmlInfo.Transform = xsltInfo;
}
</script>
<asp:xml ID="aspxmlInfo" runat="server"></asp:xml>
DEFAULT.ASPX : FIN
---
I_INFOPAGE.XSL :
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="
http://www.w3.org/1999/XSL/Transform" version="1.0">
<xsl:output method="html" indent="no" />
<xsl:param name="urlPage" />
<xsl:template match="/">
<xsl:apply-templates select="//page[userCreation=$urlPage]" />
</xsl:template>
<xsl:template match="page">
<table class="mainTable" border="0" cellpadding="0" cellspacing="0"
align="center" bgcolor="#FFFFFF">
<tr align="left" valign="top">
<td class="infoPage" style="padding-left: 209px"><xsl:value-of
select="userMiseajour" /> - <xsl:value-of select="dateMiseajour" /></td>
<td width="200" align="right" class="infoPage" style="padding-right:
8px">vu: <xsl:value-of select="vu" /></td>
</tr>
</table>
</xsl:template>
</xsl:stylesheet>
I_INFOPAGE.XSL :FIN
