wrote:

> Hi,
>
> I am new to XSLT, modifying somebody else's code:
>
> I have the following data (leaves in parallel branches):
> mystruct/myarray1[i]/myvar/var2 and
> mystruct/myarray2[i]/myvar/var3
>
> I need to implement the find the first occurence of :
> <xsl:if test="position() != last() and
> number(var2) = number(var2[position()+1]) and
> number(var3) = number(var3[position()+1])">
> <value-of select="position()">
> </xsl:if>
>
> A few questions to XSLT gurus:
> 1) Does it make sense to do in the for-each loop or it will require a
> recursion ?
> All I need is to get the position of the 1st occurrence.
> How would that recursion look like?
>
> 2) Will I be able to get a node from the parallel branch in for-each
> loop ?
> Something like:
> <xsl:for-each mystruct/myarray1[i]/myvar>
> <xsl:if test=" ...and number(../../myarray2[i]/myvar/var3) =
> number((../../myarray2[i]/myvar/var3)[position()+1]) and...">
> <value-of select="position()">
> </xsl:if>
> </xsl:for-each>)
> I know it looks awful :-(
>
> 3) Is there a way to somehow start the for-each loop
> from position other than 1 ?
> Like with j>1:
> <xsl:for-each mystruct/myarray1[i]/myvar[j]>
> ....
> </xsl:for-each>
>
> I am using XSLT 1.x
>
> Thank you in advance,
> Oleg.
>
>