"Oleg Tkachenko [MVP]" wrote:

> A bit of reflection can do this:
>
> Type enumType = typeof(velocityUom);
> foreach (FieldInfo fi in enumType.GetFields())
> {
> object[] attrs = fi.GetCustomAttributes(typeof(XmlEnumAttribute), false);
> if (attrs.Length > 0)
> {
> Console.WriteLine(((XmlEnumAttribute)attrs[0]).Name);
> }
> }
>
> --
> Oleg Tkachenko [XML MVP, MCAD]
> http://www.XmlLab.Net | http://www.XLinq.Net | http://blog.tkachenko.com
>
> Edward Clements wrote:
> > I have an enum defined as
> > public enum velocityUom
> > { /// <remarks/>
> > [System.Xml.Serialization.XmlEnumAttribute("m/s")]
> > ms,
> >
> > /// <remarks/>
> > [System.Xml.Serialization.XmlEnumAttribute("cm/a")]
> > cma,
> > ...
> > }
> >
> > This class was generated by xsd.exe, from a schema like
> > <xsd:simpleType name="velocityUom">
> > <xsd:enumeration value="m/s"/>
> > <xsd:enumeration value="cm/a"/>
> > ...
> > </xsd:restriction>
> > </xsd:simpleType>
> >
> > I would like to retrieve the XmlEnumAttribute values for this Enum so that I
> > can create a combo box with values like "m/s", "cm/a", ... so that I don't
> > have to hard-code the XML-enum values in my code.
> >
> > Is there any way to do this? the MSDN examples are only to add extra enum
> > values for a class and Enum.GetNames() just retrieves "ms", "cma", ...
> >
> > Thanks,
> >
> > Edward Clements
> >