> "Dave" <brad@pitt.org> wrote in message
> news:MPG.21127a81cb178ea8989691@news.west.cox.net...
> > I am running the following code and I get an error:
> >
> > Set xmlHttp = Server.CreateObject("MSXML2.XMLHTTP.3.0")
> > xmlHttp.Open "Get", URLToRSS, false
> > xmlHttp.Send
> > RSSXML = xmlHttp.ResponseText
> >
> > The error is:
> >
> > msxml3.dll error '800c0005'
> > The system cannot locate the resource specified.
> >
> > It points to the "xmlHttp.Send" statement.
> >
> > This code runs perfectly on my old ISP's server but not on my GoDaddy
> > server.
> >
> > Any ideas?
>
>
> Use MSXML2.ServerXMLHTTP.3.0, XMLHTTP should not be used the server context.
>
> If that doesn't fix it can you visit the URL using a browser running on the
> server?
>
> Check for any proxy server configuration on the server.

"Dave" <brad@pitt.org> wrote in message
news:MPG.21127a81cb178ea8989691@news.west.cox.net...
> I am running the following code and I get an error:
>
> Set xmlHttp = Server.CreateObject("MSXML2.XMLHTTP.3.0")
> xmlHttp.Open "Get", URLToRSS, false
> xmlHttp.Send
> RSSXML = xmlHttp.ResponseText
>
> The error is:
>
> msxml3.dll error '800c0005'
> The system cannot locate the resource specified.
>
> It points to the "xmlHttp.Send" statement.
>
> This code runs perfectly on my old ISP's server but not on my GoDaddy
> server.
>
> Any ideas?