We only enable Shared Memory and TCP/IP protocal in server side. And, those
are the error they are getting.
osql -- SQL server doesn't exist or access denied
Query Analyzer -- General network error. Check your network documentation
VS 2005 -- (without specifing TCP protocal in connection) A connection was
succssfully established with the server, but then an error occured during the
pre-login handshake. When connecting .....(provider: Named Pipes provider,
error: 0 - No process is on the ther end of the pipe)
VS 2005 -- (specify TCP protocal in connection) An error has occurred while
establishing a connection to the server. When connecting to SQL server 2005,
this failure may be caused by the fact that under the default settings ...
(provider: TCP provider: 0 -- A connection attempt failed because the
connected party didn't not properly respond after a period of tiem, or
established connection failed because connected host has failed to respond.)
Again, this developer is able to login by using my machine with his WIN
account.
After I enable Named Pipes in server. This developer is able to connect to
server on his machine by using Named Pipe.
Firewall is off in the server, so I can't think of the issue for TCP
connection on developer's machine.
Please advise. Thank you.
--
Best Regards,
Lynn
[quoted text, click to view] "Sue Hoegemeier" wrote:
> What is the exact error message and error number he gets
> when he tries to log into SQL Server?
>
> -Sue
>
> On Thu, 22 Mar 2007 10:33:45 -0700, Lynn
> <Lynn@discussions.microsoft.com> wrote:
>
> >Hi,
> >
> >SQL 2005 EE is installed on W2k3 box and firewall is off in this server.
> >From my client machine, my window account and that developer window account
> >all can login into this server with ODBC, sql client, telent to 1433 or VS
> >connection. But, this developer can't login to SQL server from him machine
> >with any appliction. He is in the same domain as server and my machine. I
> >don't know what's the reason to cause this issue now.
> >
> >Please advise. Thank you.
> >
> >Lynn
>